## In This post you will get answer of Q.

The magnetic moment associated with a circular coil of $35$ turns and radius $25 ,cm$, if it carries a current of $11 ,A$ is

Solution:

## Given $N = 35$,

$r = 25, cm$

$=25times10^{-2},m$,

$I=11,A $

Then magnetic moment associated with this circular coil

$M=NIA=NIpi r^{2}=35times11times3.14timesleft(25times10^{-2}right)^{2}$

$=75.56,A ,m^{2}$