In This post you will get answer of Q.
The magnetic moment associated with a circular coil of $35$ turns and radius $25 ,cm$, if it carries a current of $11 ,A$ is
Solution:
Given $N = 35$,
$r = 25, cm$
$=25times10^{-2},m$,
$I=11,A $
Then magnetic moment associated with this circular coil
$M=NIA=NIpi r^{2}=35times11times3.14timesleft(25times10^{-2}right)^{2}$
$=75.56,A ,m^{2}$
Solution:
Given $N = 35$,
$r = 25, cm$
$=25times10^{-2},m$,
$I=11,A $
Then magnetic moment associated with this circular coil
$M=NIA=NIpi r^{2}=35times11times3.14timesleft(25times10^{-2}right)^{2}$
$=75.56,A ,m^{2}$