> Q. The maximum and minimum distance of a comet from the sun are $ 8times {{10}^{12}}m $ and $ 1.6times {{10}^{12}}m $ . If its velocity when nearest to the sun is 60 m/s, what will be its velocity in m/s when farthest? – LIVE ANSWER TODAY

Q. The maximum and minimum distance of a comet from the sun are $ 8times {{10}^{12}}m $ and $ 1.6times {{10}^{12}}m $ . If its velocity when nearest to the sun is 60 m/s, what will be its velocity in m/s when farthest?

In This post you will get answer of Q.
The maximum and minimum distance of a comet from the sun are $ 8times {{10}^{12}}m $ and $ 1.6times {{10}^{12}}m $ . If its velocity when nearest to the sun is 60 m/s, what will be its velocity in m/s when farthest?

Solution:

According to law of conservation of angular momentum $ m{{upsilon }_{1}}{{r}_{1}}=m{{upsilon }_{2}}{{r}_{2}} $ or $ {{upsilon }_{1}}=frac{{{upsilon }_{2}}{{r}_{2}}}{{{r}_{1}}} $ $ =frac{60times 1.6times {{10}^{12}}}{8times {{10}^{12}}}=12,mtext{/}s $

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