## In This post you will get answer of Q.

The motion of particle of mass $m$ is given by $y=ut +frac{1}{2} ,gt^{2}$. The force acting on the particle is

Solution:

## Here, $y=u t+frac{1}{2} g t^{2}$

$therefore$ Velocity, $v=frac{d,y}{d ,t}$

$=u+gt$

Acceleration, $a=frac{dv}{dt}=g$

The force acting on the particle is,

$F=ma=mg$