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Q.
The period of SHM of a particle is 12 s. The phase difference between the positions at $ t=3,s $ and $ t=4s $ will be: – LIVE ANSWER TODAYSkip to content

In This post you will get answer of Q.
The period of SHM of a particle is 12 s. The phase difference between the positions at $ t=3,s $ and $ t=4s $ will be:

Solution:

The phase of particle at $ t=3,s $ is $ text{o }!!|!!text{ =}omega text{t=}left( frac{2pi }{T} right)t $ $ =frac{2pi times 3}{12}=frac{pi }{2} $ At $ t=4s $ $ text{o }!!|!!text{ =}omega t=left( frac{2pi }{T} right)t $ $ =frac{2pi times 4}{12}=frac{2pi }{3} $ Phase difference $ Delta text{o }!!|!!text{ =},text{o}{{text{ }!!|!!text{ }}_{2}}-text{o}{{text{ }!!|!!text{ }}_{1}}=frac{2pi }{3}-frac{pi }{2}=frac{pi }{6} $