## In This post you will get answer of Q.

The polarising angle for a medium is $60^Â°$. The critical angle for the medium is

Solution:

## Here, $i_p = 60^Â°$

Refractive index of the medium,

$mu=tani_{p}=tan60^{Â°}=sqrt{3}$

Now, critical angle of the medium, $i_{c}$

$=sin^{-1}left(frac{1}{mu}right)=sin^{-1}left(frac{1}{sqrt{3}}right)$