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Q. The ratio of the volume of the atom to the volume of the nucleus is of the order of

In This post you will get answer of Q.
The ratio of the volume of the atom to the volume of the nucleus is of the order of

Solution:

Radius of the atom, $R_{a}=1,Å=10^{-10},m$

Volume of the atom, $V_{a}=frac{4}{3} pi R^{3}_{a}=frac{4}{3}timespitimesleft(10^{-10}right)^{3},m^{3}$

Radius of the nucleus, $R_n=1$ fermi $=10^{-15},m$

Volume of the nucleus, $V_{n}=frac{4}{3} pi R^{3}_{n}=frac{4}{3}timespitimesleft(10^{-15}right)^3,m^{3}$

Their corresponding ratio is

$frac{V_{a}}{V_{n}}=frac{left(10^{-10}right)^{3}}{left(10^{-15}right)^{3}}=frac{10^{-30}}{10^{-45}}=10^{15}$

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