## In This post you will get answer of Q.

The resistance of the wire in the platinum resistance thermometer at ice point is $ 5,Omega $ and at steam point is $ 5.25,Omega $ . When the thermometer is inserted in an unknown hot bath its resistance is found to be $ 5.5,Omega $ . The temperature of the hot bath is

Solution:

## For resistance thermometers

$t=frac{R_{t}-R_{0}}{R_{100}-R_{0}}times100^{circ}C$

Here $R_{t}=5.5 Omega, R_{0}=5 Omega, R_{100}=5.25 Omega$

$therefore t=frac{5.5-5}{5.25-5}times100$

$=frac{0.5}{0.25}times100$

$=200^{circ},C$