> Q. The transfer ratio $beta$ of transistor is 50. The input resistance of a transistor when used in C.E. (Common Emitter) configuration is 1k$Omega$. The peak value of the collector A.C current for an A.C input voltage of 0.01V peak is – LIVE ANSWER TODAY

Q. The transfer ratio $beta$ of transistor is 50. The input resistance of a transistor when used in C.E. (Common Emitter) configuration is 1k$Omega$. The peak value of the collector A.C current for an A.C input voltage of 0.01V peak is

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The transfer ratio $beta$ of transistor is 50. The input resistance of a transistor when used in C.E. (Common Emitter) configuration is 1k$Omega$. The peak value of the collector A.C current for an A.C input voltage of 0.01V peak is

Solution:

$i_{B} = frac{V_{S}}{R_{in}}=frac{0.01}{10^{3}} = 1quad10^{5},A$

Now $beta$ of transistor is defined as

$beta_{ac}=frac{i_{c}}{i_{b}}$

or $,i_{c}=50times10^{-5}=500mu A$

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