> Q. The velocity and acceleration vectors of a particle undergoing circular motion are $vec{v =}2hat{i} mbackslash s;and $ $ vec{a} = 2hat{i} + 4hat{j} mbackslash s^{2} $ respectively at an instant of time. The radius of the circle is – – LIVE ANSWER TODAY

Q. The velocity and acceleration vectors of a particle undergoing circular motion are $vec{v =}2hat{i} mbackslash s;and $ $ vec{a} = 2hat{i} + 4hat{j} mbackslash s^{2} $ respectively at an instant of time. The radius of the circle is –

In This post you will get answer of Q.
The velocity and acceleration vectors of a particle undergoing circular motion are

$vec{v =}2hat{i} mbackslash s;and $
$ vec{a} = 2hat{i} + 4hat{j} mbackslash s^{2} $
respectively at an instant of
time. The radius of the circle is –

Solution:

It can be observed that component of
acceleration perpendicular to velocity is

a = 4 $m/s^2$

$therefore radius = frac{v^{2}}{a_{c}} = frac{left(2right)^{2}}{4} = 1 ; metre $

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