## In This post you will get answer of Q.

The velocity and acceleration vectors of a particle undergoing circular motion are

$vec{v =}2hat{i} mbackslash s;and $

$ vec{a} = 2hat{i} + 4hat{j} mbackslash s^{2} $

respectively at an instant of

time. The radius of the circle is –

Solution:

## It can be observed that component of

acceleration perpendicular to velocity is

a = 4 $m/s^2$

$therefore radius = frac{v^{2}}{a_{c}} = frac{left(2right)^{2}}{4} = 1 ; metre $