In This post you will get answer of Q.
Transformer works on $220 , V$. Its efficiency is $80%$. Output power is $8 , kW$. Primary current is approximately
Solution:
Efficiency of transformer, $eta = frac{P_{o}}{P_{i}} = frac{P_{o}}{V_{i} I_{i}}$
Here, $ eta=80% = 0.8 , P_{o} = 8 k W = 8000 W$
$ V_{i} = 220 V , I_{i} = ? $
or $ I_{i} = frac{P_{o}}{eta V_{i}} = frac{8000}{0.8 times220}= frac{1000}{22} $
$ , , , , , = 45.45 A approx 45 A.$
Solution:
Efficiency of transformer, $eta = frac{P_{o}}{P_{i}} = frac{P_{o}}{V_{i} I_{i}}$
Here, $ eta=80% = 0.8 , P_{o} = 8 k W = 8000 W$
$ V_{i} = 220 V , I_{i} = ? $
or $ I_{i} = frac{P_{o}}{eta V_{i}} = frac{8000}{0.8 times220}= frac{1000}{22} $
$ , , , , , = 45.45 A approx 45 A.$