In This post you will get answer of Q.
Truth table for the given circuit in figure is
Solution:
Truth table for the given circuit is
A
B
$C = Acdot B$
$D = bar{A} cdot B$
E = C+D
0
0
0
0
0
0
1
0
1
1
1
0
0
0
0
1
1
1
0
1
Hence, option (c) is correct.
Solution:
Truth table for the given circuit is
| A | B | $C = Acdot B$ | $D = bar{A} cdot B$ | E = C+D |
|---|---|---|---|---|
| 0 | 0 | 0 | 0 | 0 |
| 0 | 1 | 0 | 1 | 1 |
| 1 | 0 | 0 | 0 | 0 |
| 1 | 1 | 1 | 0 | 1 |
Hence, option (c) is correct.