In This post you will get answer of Q.
Two person P and Q of same height are carrying a uniform beam of length 3 m. If Q is at one end, the distance of P from the other end so that P, Q receive loads in the ratio 5 : 3 is
Solution:
Let X is distance of P from other end
$( xF_p) + (L times F_0) = W times frac{L}{2} $
where L is the length ofthe rod and W is its weight but
$W = F_P + F_Q$
(0.6 m )
Solution:
Let X is distance of P from other end
$( xF_p) + (L times F_0) = W times frac{L}{2} $
where L is the length ofthe rod and W is its weight but
$W = F_P + F_Q$
(0.6 m )