> Q. Two stones art thrown vertically upwards with the same velocity of 49m/s. If they are thrown one after the other with a time lapse of 3 second, height at which they collide is – LIVE ANSWER TODAY

Q. Two stones art thrown vertically upwards with the same velocity of 49m/s. If they are thrown one after the other with a time lapse of 3 second, height at which they collide is

In This post you will get answer of Q.
Two stones art thrown vertically upwards with the same velocity of 49m/s. If they are thrown one after the other with a time lapse of 3 second, height at which they collide is

Solution:

$s = ut – frac{1}{2} gt^2 = u(t – 3) – frac{1}{2} g(t – 3)^2$

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